tag:blogger.com,1999:blog-36296778987261193442024-02-19T09:49:32.458+01:00 M´impiccio di scienza Matemáticas y Física. Recursos didácticos.
Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.comBlogger30125tag:blogger.com,1999:blog-3629677898726119344.post-1063736489382669262015-11-07T14:52:00.001+01:002015-11-07T14:58:31.564+01:00El genio Gaudí<br />
No existe un solo modo de realizar cosas...<br />
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi2d3Z8d_LK4oiQ_GbB_TXiFDzOujt1jQvgm_ty8ZINP_gd56rWCDLusNYfuC1fBPpdroJbBkR4sGYRY1S5m1HcDkUroabjKr8fSgpzI4SZd_Av6faTiAeNoyI8SHWkRMwmoJi4OeG5-eE/s1600/catenaria-gaudi-maqueta_funicular.es.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="320" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi2d3Z8d_LK4oiQ_GbB_TXiFDzOujt1jQvgm_ty8ZINP_gd56rWCDLusNYfuC1fBPpdroJbBkR4sGYRY1S5m1HcDkUroabjKr8fSgpzI4SZd_Av6faTiAeNoyI8SHWkRMwmoJi4OeG5-eE/s320/catenaria-gaudi-maqueta_funicular.es.jpg" width="240" /></a></div>
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<a href="https://www.youtube.com/watch?v=_dg63c7pYcU">https://www.youtube.com/watch?v=_dg63c7pYcU</a>Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-18987472068318610092015-08-12T13:26:00.003+02:002015-08-12T13:36:14.412+02:00HERRAMIENTAS Y RECURSOS PARA PROFESORES<b style="font-family: Arial, Helvetica, sans-serif;"><br /></b>
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Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-62037812002462637432015-08-11T23:18:00.000+02:002015-08-12T13:09:40.314+02:00LINKS DE INTERÉS EDUCACIÓN<br />
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<a href="http://blog.tiching.com/7-consejos-para-estimular-las-inteligencias-multiples/?utm_source=tiching&utm_medium=referral" target="_blank">7 CONSEJOS PARA ESTIMULAR LAS INTELIGENCIAS MÚLTIPLES</a><br />
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<a href="http://blog.tiching.com/10-geniales-peliculas-para-trabajar-el-respeto/" target="_blank">10 PELÍCULAS DIVERTIDAS CON LAS QUE TRABAJAR EL RESPECTO</a><br />
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<a href="http://blog.tiching.com/10-peliculas-para-reflexionar-sobre-la-comunicacion/?utm_content=CMPPel%C3%ADculasComunicaci%C3%B3n&utm_source=twitter&utm_medium=referral&utm_campaign=cm" target="_blank">10 PELÍCULAS PARA REFLEXIONAR SOBRE LA COMUNICACIÓN</a><br />
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<a href="http://blog.tiching.com/15-geniales-recursos-para-trabajar-la-educacion-emocional/" target="_blank">15 GENIALES RECURSOS PARA TRABAJAR LA EDUCACIÓN EMOCIONAL</a><br />
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<br />Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-3366420799637494082015-08-11T22:02:00.000+02:002015-08-11T22:02:10.702+02:00Goleman, D. (2012). Inteligencia emocional. Editorial Kairós.<br />
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<a href="http://www.asociacionaccent.com/informa/_textosdeestudio/text_habilidades_sociales_inteligencia_emocional.pdf" target="_blank">http://www.asociacionaccent.com/informa/_textosdeestudio/text_habilidades_sociales_inteligencia_emocional.pdf</a><br />
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Mapa mental de la inteligencia emocional<br />
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<br />Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-88643569673916186702015-08-05T11:49:00.002+02:002015-08-05T11:49:46.034+02:00Aplicando trigonometría para calcular la separación entre un monumento y una persona.<a href="http://math2me.com/playlist/curiosidades/la-distancia-entre-el-obelisco-y-yo-mnto-washington" target="_blank">http://math2me.com/playlist/curiosidades/la-distancia-entre-el-obelisco-y-yo-mnto-washington</a>Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-50667174682806624952015-05-19T13:01:00.000+02:002015-05-21T19:46:58.110+02:00EJERCICIOS RESUELTOS RECTAS EN EL PLANO. 4ºESO OPCIÓN B<div class="separator" style="clear: both; text-align: center;">
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GEOMETRÍA ANALÍTICA II </div>
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TEORÍA ECUACIONES DE LA RECTA Y EJEMPLOS</div>
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<a href="https://drive.google.com/file/d/0B-w039OFBj-1b2FHNkEydS1ERXM/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1b2FHNkEydS1ERXM/view?usp=sharing</a></div>
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TEORÍA Y EJERCICIOS<br />
<a href="https://drive.google.com/file/d/0B-w039OFBj-1djRaQjJGeE1Ga1U/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1djRaQjJGeE1Ga1U/view?usp=sharing</a><br />
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EJERCICIOS<br />
<a href="https://drive.google.com/file/d/0B-w039OFBj-1VVc3MmVXQnFFbU0/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1VVc3MmVXQnFFbU0/view?usp=sharing</a><br />
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<a href="https://drive.google.com/file/d/0B-w039OFBj-1bVJWYXl4R1V4eHM/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1bVJWYXl4R1V4eHM/view?usp=sharing</a><br />
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<a href="https://drive.google.com/file/d/0B-w039OFBj-1SnRrWHJFYUFGX1U/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1SnRrWHJFYUFGX1U/view?usp=sharing</a><br />
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<a href="https://drive.google.com/file/d/0B-w039OFBj-1UW5ldmlQVG1IMjg/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1UW5ldmlQVG1IMjg/view?usp=sharing</a><br />
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Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com1tag:blogger.com,1999:blog-3629677898726119344.post-48694489538200442242015-05-18T23:03:00.000+02:002015-05-21T19:47:08.883+02:00EJERCICIOS RESUELTOS PUNTOS Y VECTORES EN EL PLANO. 4ºESO B<br />
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GEOMETRÍA ANALÍTICA I </div>
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TEORÍA<br />
<a href="http://es.slideshare.net/luisenberlin/4-esoa-tema09vectores-y-rectas-en-el-plano" target="_blank">http://es.slideshare.net/luisenberlin/4-esoa-tema09vectores-y-rectas-en-el-plano</a><br />
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TEORÍA Y EJERCICIOS<br />
<a href="https://drive.google.com/file/d/0B-w039OFBj-1NkxMbXBmSnVWY0k/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1NkxMbXBmSnVWY0k/view?usp=sharing</a><br />
<a href="https://drive.google.com/file/d/0B-w039OFBj-1Y3JEckhjak1RYUk/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1Y3JEckhjak1RYUk/view?usp=sharing</a><br />
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EJERCICIOS<br />
<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhDPZn1FAOY6pZx2MsEIqMY4HwPggN2u6QL0YkAhps6CdnmJJa8OWoXJGMmTOwh50CUdP7fT_OsV7kvOGDeJPSvsFigt-pvcRrbmvW7due9Gdo5yIWwQPkkqIHn4fQUFk5AYpBe39ajG9M/s1600/images.png" imageanchor="1" style="clear: right; float: right; margin-bottom: 1em; margin-left: 1em;"><img border="0" height="116" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhDPZn1FAOY6pZx2MsEIqMY4HwPggN2u6QL0YkAhps6CdnmJJa8OWoXJGMmTOwh50CUdP7fT_OsV7kvOGDeJPSvsFigt-pvcRrbmvW7due9Gdo5yIWwQPkkqIHn4fQUFk5AYpBe39ajG9M/s200/images.png" width="200" /></a><a href="https://drive.google.com/file/d/0B-w039OFBj-1SE5LNFRSNzJNd2c/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1SE5LNFRSNzJNd2c/view?usp=sharing</a><br />
<a href="https://drive.google.com/file/d/0B-w039OFBj-1M1FkOXMwX0prbnc/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1M1FkOXMwX0prbnc/view?usp=sharing</a><br />
<a href="http://www.xtec.cat/~jbartrol/vectores/manual/vectores.html" target="_blank">http://www.xtec.cat/~jbartrol/vectores/manual/vectores.html</a><br />
<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhCJ8Au5l1QYapRYQIkLLe48nGO4ntJXOrfx3VnLsHpFemaBWxXFBzXS51S0CMS8Scg7PEUsXIdCFRaDT20CgDiiJyxhAVfFaGTWwfB4Cpx1RqIfEyaGCS2RsvItb_Ov-uT0TsnV1CVFCA/s1600/Vectores(3).JPG" imageanchor="1" style="clear: left; float: left; margin-bottom: 1em; margin-right: 1em;"><img border="0" height="230" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhCJ8Au5l1QYapRYQIkLLe48nGO4ntJXOrfx3VnLsHpFemaBWxXFBzXS51S0CMS8Scg7PEUsXIdCFRaDT20CgDiiJyxhAVfFaGTWwfB4Cpx1RqIfEyaGCS2RsvItb_Ov-uT0TsnV1CVFCA/s320/Vectores(3).JPG" width="320" /></a><br />
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<br />Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-23204609267773100932015-04-26T20:02:00.002+02:002015-04-26T20:02:54.609+02:00TRIGONOMETRÍA: TALES Y LAS SOMBRAS<br />
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjK11xQB42OumS9GPuXvm9eVV1N-Dpo87FYNoz2puqduet-xDXRPRQ7xbGPPPAiW-bL9T69fojmyU01VUsCCsB4Vuhwn9w_qS0eSBmwCrf_0sFZzs2I_G34MozVdS7i2esrBMo8Y-bEBhg/s1600/2015-04-26_200157.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjK11xQB42OumS9GPuXvm9eVV1N-Dpo87FYNoz2puqduet-xDXRPRQ7xbGPPPAiW-bL9T69fojmyU01VUsCCsB4Vuhwn9w_qS0eSBmwCrf_0sFZzs2I_G34MozVdS7i2esrBMo8Y-bEBhg/s1600/2015-04-26_200157.jpg" height="181" width="320" /></a></div>
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<a href="http://recursostic.educacion.es/gauss/web/materiales_didacticos/eso/actividades/geometria/trigonometria/tales_sombras/actividad.html" target="_blank">http://recursostic.educacion.es/gauss/web/materiales_didacticos/eso/actividades/geometria/trigonometria/tales_sombras/actividad.html</a>Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-61188604015035398632015-04-26T20:01:00.001+02:002015-04-26T20:01:15.355+02:00TRIGONOMETRÍA: LA PENDIENTE DE UNA CARRETERA<br />
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<a href="http://recursostic.educacion.es/gauss/web/materiales_didacticos/eso/actividades/geometria/trigonometria/pendiente_carretera/actividad.html" target="_blank">http://recursostic.educacion.es/gauss/web/materiales_didacticos/eso/actividades/geometria/trigonometria/pendiente_carretera/actividad.html</a>Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-65329416282685698692015-04-26T19:59:00.001+02:002015-04-26T19:59:23.283+02:00TRIGONOMETRÍA: LA ESCALERA DE LOS BOMBEROS<div class="separator" style="clear: both; text-align: center;">
<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgJZOEMwUE4gmt6tPZvoNMrfDgehEd5yyk_csOzRkIzeSPK_SSQf5EoD-dfsEoTfJEFzyx9hRPvMqJkhSu2O1zj7AhJZZY6bthqwhmAwELMTmeqZcD9JbPNss8h2XNwRxLuQMNo5rUg6mU/s1600/2015-04-26_195648.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgJZOEMwUE4gmt6tPZvoNMrfDgehEd5yyk_csOzRkIzeSPK_SSQf5EoD-dfsEoTfJEFzyx9hRPvMqJkhSu2O1zj7AhJZZY6bthqwhmAwELMTmeqZcD9JbPNss8h2XNwRxLuQMNo5rUg6mU/s1600/2015-04-26_195648.jpg" height="157" width="320" /></a></div>
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<a href="http://recursostic.educacion.es/gauss/web/materiales_didacticos/eso/actividades/geometria/trigonometria/escalera_bomberos/actividad.html" target="_blank">http://recursostic.educacion.es/gauss/web/materiales_didacticos/eso/actividades/geometria/trigonometria/escalera_bomberos/actividad.html</a></div>
Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-7251018450025632062015-04-18T14:58:00.000+02:002015-04-19T18:36:51.185+02:00EJERCICIO TRIÁNGULOS. TIRANTES DEL PUENTE DE RANDE.<ul style="display: inline-block; font-family: Arial, Verdana, Helvetica, sans-serif; list-style: none; margin: 0px 0px 1em; padding: 0px; width: 20em;"><span style="background-color: #76a5af; color: #fff2cc;">
<li style="background-attachment: initial; background-clip: initial; background-color: initial; background-image: url(http://www.acciona-infraestructuras.es/img/bullet_general3.gif); background-origin: initial; background-position: 0px 0.4em; background-repeat: no-repeat; background-size: initial; margin-bottom: 0.5em; padding-left: 1em;"><strong>Obra:</strong> Puente de Rande en Vigo.</li>
<li style="background-attachment: initial; background-clip: initial; background-color: initial; background-image: url(http://www.acciona-infraestructuras.es/img/bullet_general3.gif); background-origin: initial; background-position: 0px 0.4em; background-repeat: no-repeat; background-size: initial; margin-bottom: 0.5em; padding-left: 1em;"><strong>Ubicación:</strong> Vigo, Pontevedra. (Galicia). España.</li>
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<span style="background-color: #76a5af; color: #fff2cc; font-size: small;">Descripción:</span></h5>
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<span style="background-color: #76a5af; color: #fff2cc;">Constituye una obra singular dentro de la Autopista del Atlántico, que une La Coruña y Vigo, cruzando la ría de Vigo por el estrecho de Rande y evitando dar un rodeo de más de 50 km. por toda la ría. Mide 1.558 m. de longitud total entre el puente metálico más viaductos de acceso. Las columnas que lo sostienen tienen una altura de 148 m. sobre el fondo marino.</span></div>
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<span style="background-color: #76a5af; color: #fff2cc;">El puente en su tramo central es del tipo atirantado. Consta de un tablero metálico con un ancho total de 23,46 m., que permite una doble circulación en cada sentido y que se encuentra a una cota de 50 m. sobre el nivel del mar. La luz libre entre las pilas centrales es de 400,14 m., que lo situaron en su momento en el segundo con más luz del mundo para ese tipo de puentes, entre las pilas centrales y las de tierra hay un tramo de 147,42 m. a ambos lados, dando un total de longitud para el puente central atirantado de 694,98 m. El tablero está suspendido de cables rectos anclados en los bordes del mismo y en las cabezas de las pilas centrales. Las pilas centrales de hormigón armado tienen un altura de 128,10 sobre el nivel del mar y descansan sobre unas fundaciones que llegan a la cota menos 20, cimentadas directamente sobre la roca del fondo de la ría.</span></div>
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<span style="background-color: #76a5af; color: #fff2cc;">El conjunto se completa con dos viaductos de acceso, formados por dos vigas de cajón continuas, una por cada calzado, de hormigón pretensado. La longitud total de los viaductos es de 863 metros.</span></div>
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<span style="background-color: #76a5af; color: #fff2cc;">Los autores del proyecto fueron Florencio del Pozo, Fabrizio de Miranda y Alfredo Passaro. En 1979 obtuvo el Premio Europeo a la Construcción metálica más destacada.</span></div>
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<a href="https://www.youtube.com/watch?v=YNPuzWON_hk" target="_blank">https://www.youtube.com/watch?v=YNPuzWON_hk</a></div>
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<span style="color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;"><b style="background-color: #76a5af;">EJERCICIO:</b></span></div>
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<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">Con los datos obtenidos en la descripción anterior, calcula la longitud de los 4 tirantes más largos que van desde cada pila al centro y a los extremos del puente respectivamente.</span></div>
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<span style="color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;"><b style="background-color: #76a5af;">RESOLUCIÓN</b></span></div>
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<span style="background-color: #76a5af; color: #fff2cc;">Con la explicación podemos recadar los siguientes datos:</span></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgi0fgANwM9ei2hj05DO7V5WpLYB-qSpyP3F2Wy9hv_8aR3otJ8KbfFwKUtzLO_O0St5WBWDZAAtTNKDuM5qZboONW0McqKzVYQtH5MPgQEydhQ-LbCk9V0QwKjWEu0rarTXFDp201tDrQ/s1600/15963.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><span style="background-color: #76a5af; color: #fff2cc;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgi0fgANwM9ei2hj05DO7V5WpLYB-qSpyP3F2Wy9hv_8aR3otJ8KbfFwKUtzLO_O0St5WBWDZAAtTNKDuM5qZboONW0McqKzVYQtH5MPgQEydhQ-LbCk9V0QwKjWEu0rarTXFDp201tDrQ/s1600/15963.jpg" /></span></a></div>
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<span style="background-color: #76a5af; color: #fff2cc;">Tenemos que hallar la longitud de los tirantes 1,2,3 y 4.</span></div>
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<span style="background-color: #76a5af; color: #fff2cc;">Para ello nos quedamos con un sólo triángulo, puesto que son totalmente simétricos.</span></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg8TF5hrAxcbkyd7DLlCGTao25OOySqIWD7zK-DZt5kFS6GL0CkQBD7dgF25HBmwWuci1u2cUpuVJHUTnqim3nPByjbyG_gLrA7cKb4gsDQF_WByOptTLIaNch6fdbpxfpdbejDCOkpEbE/s1600/123655.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><span style="background-color: #76a5af; color: #fff2cc;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg8TF5hrAxcbkyd7DLlCGTao25OOySqIWD7zK-DZt5kFS6GL0CkQBD7dgF25HBmwWuci1u2cUpuVJHUTnqim3nPByjbyG_gLrA7cKb4gsDQF_WByOptTLIaNch6fdbpxfpdbejDCOkpEbE/s1600/123655.jpg" height="180" width="320" /></span></a></div>
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<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">1.</span></div>
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<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">tg<span style="line-height: 18.2000007629395px;">α=200,07/78,10= 2,56</span></span></div>
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<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;"><span style="line-height: 18.2000007629395px;">tg-1 2,56</span><span style="line-height: 18.2000007629395px;">= 68,67</span><span style="line-height: 27.6000003814697px;">°</span></span></div>
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<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif;"><span style="font-size: large;">90-68,67=21,33</span><span style="line-height: 18.3999996185303px;"><span style="font-size: large;">°</span></span></span></div>
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<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif;"><span style="font-size: large;">cos21,33</span><span style="line-height: 18.3999996185303px;"><span style="font-size: large;">°=78,10/Long1</span></span></span></div>
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<span style="line-height: 18.3999996185303px;"><span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">Long 1=83,84 m</span></span></div>
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<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">2.</span></div>
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<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">h²=c²+c²</span></div>
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<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">h²= 200,07²+78,10²</span></div>
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<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">h=214,77 m</span></div>
<div>
<span style="line-height: 18.3999996185303px;"><span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;"><br /></span></span></div>
<div>
<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">3.</span></div>
<div>
<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;"><br /></span></div>
<div>
<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">214,77 m</span></div>
<div>
<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">4.</span></div>
<div>
<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;"><br /></span></div>
<div>
<span style="background-color: #76a5af; color: #fff2cc; font-family: Arial, Helvetica, sans-serif; font-size: large;">83,84 m</span></div>
<div style="clear: none; font-family: Arial, Verdana, Helvetica, sans-serif; line-height: 1.5em; margin-bottom: 1.5em; padding: 0px;">
<br /></div>
Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-28276537894199271142015-04-18T13:59:00.000+02:002015-04-18T13:59:07.742+02:00CUESTIONARIO TRIGONOMETRÍA 2: RESOLUCIÓN DE TRIÁNGULOS<a href="http://my.questbase.com/take.aspx?pin=7687-4456-9150" target="_blank">http://my.questbase.com/take.aspx?pin=7687-4456-9150</a><br />
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<br />Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-12624047640313055422015-04-15T20:58:00.002+02:002015-04-15T21:16:34.549+02:00EJERCICIO RESUELTO TRIGONOMETRÍA: HALLAR LA INCLINACIÓN DE LA TORRE DE PISA<span style="font-family: "Arial","sans-serif"; mso-fareast-language: ES; mso-no-proof: yes;"> </span><br />
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<br />
<a href="https://drive.google.com/file/d/0B-w039OFBj-1RU4wUWxsZ0NLZ2s/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1RU4wUWxsZ0NLZ2s/view?usp=sharing</a>Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-42975432437350014972015-04-14T20:29:00.001+02:002015-04-14T20:37:30.629+02:00EVALUACIÓN INICIAL DE TRIGONOMETRÍA CON MOUSE MISCHIEF<br />
<a href="https://drive.google.com/file/d/0B-w039OFBj-1WlVtS1B4LVVianM/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1WlVtS1B4LVVianM/view?usp=sharing</a><br />
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<br />Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-32716846027655777042015-04-13T13:43:00.000+02:002015-05-27T13:01:28.687+02:00TEST TRIGONOMETRÍA 1: RAZONES TRIGONOMÉTRICAS DEL ANGULO AGUDO EN EL TRIÁNGULO RECTÁNGULO<br />
<a href="http://my.questbase.com/take.aspx?pin=6769-2715-0527" target="_blank">http://my.questbase.com/take.aspx?pin=6769-2715-0527</a><br />
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Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-20584669357069528642015-04-11T15:53:00.003+02:002015-04-14T20:14:12.921+02:00TRABAJO EN GRUPO TRIGONOMETRÍA: HALLAR LA ALTURA DEL COLEGIO<br />
<br />
<a href="https://drive.google.com/file/d/0B-w039OFBj-1NDBLeWphUERkZGs/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1NDBLeWphUERkZGs/view?usp=sharing</a><br />
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Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-86585193263525709132015-04-08T21:02:00.001+02:002015-04-13T20:05:24.049+02:00APLICACIONES DE LA TRIGONOMETRÍA<div class="separator" style="clear: both; text-align: center;">
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<br />Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-78872797782484515062015-04-08T00:58:00.002+02:002015-04-13T20:05:00.403+02:00CUESTIONARIO TRIGONOMETRÍA / EVALUACIÓN INICIAL TEMA<br />
<a href="http://my.questbase.com/take.aspx?pin=9298-7057-1582" target="_blank">http://my.questbase.com/take.aspx?pin=9298-7057-1582</a><br />
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<br />Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-25362314947469515082015-03-26T23:27:00.001+01:002015-04-16T09:57:46.970+02:00TEOREMA DEL SENO Y TEOREMA DEL COSENO: EJERCICIOS RESUELTOS<h2 style="color: #0d3c62; font-family: Arial, Helvetica, sans-serif; margin: 0px 5px 0px 0px; outline: 0px; padding: 0px;">
<div align="center" class="MsoNormal" style="color: black; font-family: 'Times New Roman'; font-size: medium; font-weight: normal; text-align: center;">
<b><u><span style="font-family: 'Trebuchet MS', sans-serif; font-size: 22pt; line-height: 33.7333335876465px;">TEOREMA DEL SENO<o:p></o:p></span></u></b></div>
<div align="center" class="MsoNormal" style="color: black; font-family: 'Times New Roman'; font-size: medium; font-weight: normal; text-align: center;">
<span style="font-family: 'Trebuchet MS', sans-serif;"><br /></span>
<span style="font-family: 'Trebuchet MS', sans-serif;">“En un triángulo cada lado es directamente proporcional al seno del ángulo opuesto”</span></div>
</h2>
<div>
<br /></div>
<div>
<br /></div>
<div class="separator" style="clear: both; text-align: center;">
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgGoh_35EZuJWkK2Dol-bwDelbzwIH9QA5-mGdhv3PLQ6JmIpMAYtP397vcbsjGPMv6Ik3eVoJI18E4h3cDjFpHDOaPJsHETSWl_VXUc9Ah3bopTM4DHOzq9pSJxodZaoXSFuQO0HI0Xr0/s1600/95.gif" imageanchor="1" style="clear: right; float: right; margin-bottom: 1em; margin-left: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgGoh_35EZuJWkK2Dol-bwDelbzwIH9QA5-mGdhv3PLQ6JmIpMAYtP397vcbsjGPMv6Ik3eVoJI18E4h3cDjFpHDOaPJsHETSWl_VXUc9Ah3bopTM4DHOzq9pSJxodZaoXSFuQO0HI0Xr0/s1600/95.gif" height="39" width="200" /></a></div>
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<u><span style="font-family: "Trebuchet MS","sans-serif";"><br /></span></u></div>
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<span style="font-family: 'Trebuchet MS', sans-serif;"> <u>APLICACIONES:</u></span><span style="font-family: "Trebuchet MS","sans-serif";"> <o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: "Trebuchet MS","sans-serif";"> Resolver
un triángulo cuando tenemos: </span><br />
<ol>
<li><span style="font-family: 'Trebuchet MS', sans-serif; text-indent: -18pt;">Dos ángulos y un lado</span></li>
<li><span style="font-family: 'Trebuchet MS', sans-serif; text-indent: -18pt;">Los lados y el ángulo opuesto a
uno de ellos.</span></li>
</ol>
</div>
<span style="font-family: 'Trebuchet MS', sans-serif; text-indent: -18pt;">
</span>
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<ul>
</ul>
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<span style="font-family: "Trebuchet MS","sans-serif";"> </span><b><u><span style="font-family: "Trebuchet MS","sans-serif"; font-size: 22.0pt; line-height: 115%;">TEOREMA
DEL COSENO<o:p></o:p></span></u></b></div>
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<span style="font-family: 'Trebuchet MS', sans-serif;"><br /></span></div>
<div align="center" class="MsoNormal" style="text-align: center;">
<span style="font-family: 'Trebuchet MS', sans-serif;">“En un
triángulo el cuadrado de cada lado es igual a la suma de los cuadrados de los
otros dos menos el doble producto del producto de ambos por el coseno del
ángulo que forman.</span>”</div>
<div class="MsoNormal">
<o:p></o:p></div>
<div align="center" class="MsoNormal" style="margin-bottom: 6.0pt; text-align: center;">
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgN0Yf6PlqZ0MWBy4OJVkk7y3MUfm6BF87k6I2naZSskELPwxq9WjBC5oRGHRCi_jjNKkscljo2raQOJjjCFnDiVrR_ONf5mxN6kYpfkEgxaqKdY-NszLyRqbPW44IKNQR_F4PHk336KCI/s1600/196px-Triangle_with_notations_2.svg.png" imageanchor="1" style="clear: left; float: left; margin-bottom: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgN0Yf6PlqZ0MWBy4OJVkk7y3MUfm6BF87k6I2naZSskELPwxq9WjBC5oRGHRCi_jjNKkscljo2raQOJjjCFnDiVrR_ONf5mxN6kYpfkEgxaqKdY-NszLyRqbPW44IKNQR_F4PHk336KCI/s1600/196px-Triangle_with_notations_2.svg.png" height="116" width="200" /></a><b><span style="color: #1f497d; font-family: "Trebuchet MS","sans-serif"; font-size: 14.0pt; line-height: 115%; mso-themecolor: text2;"><br /></span></b></div>
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<b><span style="color: #1f497d; font-family: "Trebuchet MS","sans-serif"; font-size: 14.0pt; line-height: 115%; mso-themecolor: text2;">a²
= b² + c² - 2·b·c·cosÂ<o:p></o:p></span></b></div>
<div align="center" class="MsoNormal" style="margin-bottom: 6.0pt; text-align: center;">
<b><span style="color: #1f497d; font-family: "Trebuchet MS","sans-serif"; font-size: 14.0pt; line-height: 115%; mso-themecolor: text2;">b²
= a² + c² - 2·a·c·cosB<o:p></o:p></span></b></div>
<div align="center" class="MsoNormal" style="margin-bottom: 6.0pt; text-align: center;">
<b><span style="color: #1f497d; font-family: "Trebuchet MS","sans-serif"; font-size: 14.0pt; line-height: 115%; mso-themecolor: text2;">c²
= a² + b² - 2·a·b·cosC<o:p></o:p></span></b></div>
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<b><span style="color: #1f497d; font-family: "Trebuchet MS","sans-serif"; font-size: 14.0pt; line-height: 115%; mso-themecolor: text2;"><br /></span></b></div>
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<u><span style="font-family: "Trebuchet MS","sans-serif";">APLICACIONES:</span></u><span style="font-family: "Trebuchet MS","sans-serif";"> <o:p></o:p></span></div>
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<span style="font-family: "Trebuchet MS","sans-serif";">Resolver
un triángulo cuando tenemos: <o:p></o:p></span></div>
<div class="MsoListParagraphCxSpFirst" style="mso-list: l0 level1 lfo2; text-indent: -18.0pt;">
</div>
<ol>
<li><span style="font-family: 'Trebuchet MS', sans-serif; text-indent: -18pt;"> Conocemos los tres lados.</span></li>
<li><span style="font-family: 'Trebuchet MS', sans-serif; text-indent: -18pt;"> </span><span style="font-family: 'Trebuchet MS', sans-serif; text-indent: -18pt;">Dos lados y el ángulo opuesto a
uno de ellos.</span></li>
<li><span style="font-family: 'Trebuchet MS', sans-serif; text-indent: -18pt;"> </span><span style="font-family: 'Trebuchet MS', sans-serif; text-indent: -18pt;">Dos lados y el ángulo que
forman.</span></li>
</ol>
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<span style="font-family: Trebuchet MS, sans-serif;"><br /></span></div>
<div>
<span style="font-family: Trebuchet MS, sans-serif;"> EJERCICIOS RESUELTOS PARA PRACTICAR</span></div>
<div>
<span style="font-family: Trebuchet MS, sans-serif;"><br /></span></div>
<div>
<a href="http://www.cajondeciencias.com/Descargas%20mate2/ER%20teoremas%20seno%20y%20coseno.pdf" target="_blank">http://www.cajondeciencias.com/Descargas%20mate2/ER%20teoremas%20seno%20y%20coseno.pdf</a><br />
<br />
<a href="http://www.uv.es/lonjedo/esoProblemas/unidad6trigonometria.pdf" target="_blank">http://www.uv.es/lonjedo/esoProblemas/unidad6trigonometria.pdf</a><br />
<br />
<a href="http://www.amolasmates.es/almacen/4eso_op_B/fichas_anaya/trigonometria/resol_triang_cualq.pdf" target="_blank">http://www.amolasmates.es/almacen/4eso_op_B/fichas_anaya/trigonometria/resol_triang_cualq.pdf</a><br />
<br />
<a href="http://jgvaldemora.org/blog/matematicas/wp-content/uploads/2013/02/TEMA8_PROBLEMAS_M%C3%89TRICOS.pdf" target="_blank">http://jgvaldemora.org/blog/matematicas/wp-content/uploads/2013/02/TEMA8_PROBLEMAS_M%C3%89TRICOS.pdf</a><br />
<br />
TEORÍA<br />
<br />
<a href="http://www.vitutor.net/1/21.html" target="_blank">http://www.vitutor.net/1/21.html</a><br />
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<div>
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Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-69569732606205370202015-03-26T23:27:00.000+01:002015-03-26T23:27:04.089+01:00TRIÁNGULO RECTÁNGULO: EJERCICIOS RESUELTOS<br />
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<br />
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<div class="separator" style="clear: both; text-align: center;">
<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgW_P5ZgC5hCfmiP4hxjs1Ao2dWa1hMF3G5TpbqaIWOh3gkizeItMqlUqy_hkBjANuH6_KS2R0WGK_AvUzKXyJaXmV2dVKoPYr47HxwnVAxwpPD3WHP_zaj_SUpbmP0FZaP1tZ1sZKCTgs/s1600/2015-03-26_232548.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgW_P5ZgC5hCfmiP4hxjs1Ao2dWa1hMF3G5TpbqaIWOh3gkizeItMqlUqy_hkBjANuH6_KS2R0WGK_AvUzKXyJaXmV2dVKoPYr47HxwnVAxwpPD3WHP_zaj_SUpbmP0FZaP1tZ1sZKCTgs/s1600/2015-03-26_232548.jpg" height="217" width="640" /></a></div>
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EJERCICIOS RESUELTOS<br />
<a href="https://sites.google.com/site/eet285trigonometria/Teorema-de-Pitgoras/problemas-con-triangulos-rectangulos" target="_blank">https://sites.google.com/site/eet285trigonometria/Teorema-de-Pitgoras/problemas-con-triangulos-rectangulos</a><br />
<a href="http://www.uv.es/lonjedo/esoProblemas/unidad6trigonometria.pdf" target="_blank">http://www.uv.es/lonjedo/esoProblemas/unidad6trigonometria.pdf</a><br />
<a href="http://www.vadenumeros.es/cuarto/triangulos-rectangulos.htm" target="_blank">http://www.vadenumeros.es/cuarto/triangulos-rectangulos.htm</a><br />
<br />Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-77546796975850410622015-03-25T23:01:00.001+01:002015-03-25T23:03:58.613+01:00EJERCICIO PUENTE TRIÁNGULOS 4 ESO<div class="MsoNormal" style="text-align: center;">
<span style="font-family: "Trebuchet MS","sans-serif";">Un
puente metálico tiene 1 km de longitud, debido al calor dilata 20 cm. Si no se
hubiese previsto un medio para absorber esta dilatación el puente se levantaría
formando un triángulo isósceles de altura h. La base sería el puente antes de
la dilatación. ¿ Cuánto valdría h?<o:p></o:p></span></div>
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<span style="font-family: "Trebuchet MS","sans-serif";"><br /></span></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhfB_ziH3acJEi-oa2ka8GW7-Qld6_rFytUldXhQKcGcbclgts4jR7CLGHKJNJF5EEJl4NN5eiTRltBIeuec5VdQfvRSudeqgscgorKdYCRdjL2Up7UkGZW6RhkXo6FUfnadYA-1Ynl8hk/s1600/1.2.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhfB_ziH3acJEi-oa2ka8GW7-Qld6_rFytUldXhQKcGcbclgts4jR7CLGHKJNJF5EEJl4NN5eiTRltBIeuec5VdQfvRSudeqgscgorKdYCRdjL2Up7UkGZW6RhkXo6FUfnadYA-1Ynl8hk/s1600/1.2.jpg" height="149" width="320" /></a></div>
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<br /></div>
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<span style="font-family: "Trebuchet MS","sans-serif";">El
puente mide 1 km, si se parte del supuesto de que se deforma como un triángulo isósceles, ,podremos
establecer una simetría a ambos lados del punto medio del puente. <o:p></o:p></span></div>
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<span style="font-family: "Trebuchet MS","sans-serif";">Cómo
debemos calcular h, el triángulo isósceles lo dividiremos en dos triángulos rectángulos
idénticos. <o:p></o:p></span></div>
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</div>
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<span style="font-family: "Trebuchet MS","sans-serif";">Como
se indica en la figura:<o:p></o:p></span></div>
<div style="text-align: center;">
</div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg-DshBd_57m-xBXZ16F40y69gGxna-m1pzQHqPLgcJpkcfaBT2ZuN8NquJSlD7BwSHJwBH-XvdyzuxVIKUTfRjiXthmB24mXlxBmvAF52BYDz7_L4pZuWSme9lVgdp-zDhYLj9Gy-hCmg/s1600/foto+def+1.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg-DshBd_57m-xBXZ16F40y69gGxna-m1pzQHqPLgcJpkcfaBT2ZuN8NquJSlD7BwSHJwBH-XvdyzuxVIKUTfRjiXthmB24mXlxBmvAF52BYDz7_L4pZuWSme9lVgdp-zDhYLj9Gy-hCmg/s1600/foto+def+1.jpg" height="201" width="320" /></a></div>
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<div class="MsoNormal" style="text-align: center;">
<span style="font-family: "Trebuchet MS","sans-serif";">Si el
puente mide 1000 m, la mitad serán 1000/2 = 500<o:p></o:p></span></div>
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<span style="font-family: "Trebuchet MS","sans-serif";">Si
dilatase, la hipotenusa marcaría la deformación supuesta. Se deduce que si en
1000 m se deforma 20 cm; en 500 m serán 10cm. <o:p></o:p></span></div>
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<span style="font-family: "Trebuchet MS","sans-serif";">A
partir del triángulo rectángulo deducido, calculamos h<o:p></o:p></span></div>
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<span lang="EN-US" style="font-family: "Trebuchet MS","sans-serif"; mso-ansi-language: EN-US;">Hip²=cat²+cat²<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: center;">
<span lang="EN-US" style="font-family: "Trebuchet MS","sans-serif"; mso-ansi-language: EN-US;">500,1 ² - 500² = h²<o:p></o:p></span></div>
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</div>
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<span lang="EN-US" style="font-family: "Trebuchet MS","sans-serif"; mso-ansi-language: EN-US;">H= 10 m<o:p></o:p></span></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjSXA5OPCLZ2hLSjaxfphxtR5YfHE8rEeMKin05i86T5j7eVh7zrk4JTpYUTKhMGfGEJFFOSPUI07qmLsPQGeWvpoY8n0iZN7WxTrnPLWOy4OzLA8WzcA37NDDl0VFO5YXrBwIMxo-uZA8/s1600/cespez+y+triang+rojo.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjSXA5OPCLZ2hLSjaxfphxtR5YfHE8rEeMKin05i86T5j7eVh7zrk4JTpYUTKhMGfGEJFFOSPUI07qmLsPQGeWvpoY8n0iZN7WxTrnPLWOy4OzLA8WzcA37NDDl0VFO5YXrBwIMxo-uZA8/s1600/cespez+y+triang+rojo.jpg" height="198" width="320" /></a></div>
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<span style="font-family: "Trebuchet MS","sans-serif";"><a href="https://drive.google.com/file/d/0B-w039OFBj-1OHVJT3UxZ19QdDQ/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1OHVJT3UxZ19QdDQ/view?usp=sharing</a></span></div>
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Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-79435998742427553172015-03-24T01:53:00.003+01:002015-03-25T23:05:47.844+01:00FÍSICA: EJERCICIOS PLANOS INCLINADOS<br />
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<span style="font-family: "Trebuchet MS","sans-serif"; font-size: 14.0pt; line-height: 115%;">Un señor estaciona en doble fila su coche en una
carretera con una pendiente del 80%, únicamente deja el vehículo con el freno de mano
y sin la marcha puesta. En el coche deja a su hijo que juega con el freno de
mano, jugando lo baja y comienza a descender, el vehículo circula con
neumáticos nuevos por una carretera de asfalto normal seco y posteriormente por un camino de barro.<o:p></o:p></span></div>
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<br /></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjLsZ2xhAP1LiuSBOFCwISTw1723EPuB6yTyHg7e3vrYXQTNFe97VzSaTLOk2yHr9wTbj5FDs_7yZ8BZFnHU-qOYWYd2ZAplsmMgp5EyyYeIum0eiSBNozvl7X0DtvjTOgwVnS4OqZRLxM/s1600/thump_1844883coeficientes-de-roza.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjLsZ2xhAP1LiuSBOFCwISTw1723EPuB6yTyHg7e3vrYXQTNFe97VzSaTLOk2yHr9wTbj5FDs_7yZ8BZFnHU-qOYWYd2ZAplsmMgp5EyyYeIum0eiSBNozvl7X0DtvjTOgwVnS4OqZRLxM/s1600/thump_1844883coeficientes-de-roza.jpg" height="177" width="320" /></a>Escogeremos siempre el μ<span style="background-color: white; color: #252525; font-family: sans-serif; font-size: 14px; line-height: 22.3999996185303px;"> más</span> desfavorable</div>
<o:p></o:p><br />
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<o:p>a) Calcula el t que tarda en recorrer la rampa.</o:p><br />
<o:p><br /></o:p>
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</div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh53GGAAO_w4dl06RlEmtfaKySJ99uuwNfmAjoGrPx0HfoJKuuXFK7xZEZxZtNVdmIgmcPRFJIqxQkaw6fyZOjZ_7totWC-_eWAWA9PE_UmZL6KkVRxFTPtMAVn4S8bP9XiPp93zuqEd38/s1600/456.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh53GGAAO_w4dl06RlEmtfaKySJ99uuwNfmAjoGrPx0HfoJKuuXFK7xZEZxZtNVdmIgmcPRFJIqxQkaw6fyZOjZ_7totWC-_eWAWA9PE_UmZL6KkVRxFTPtMAVn4S8bP9XiPp93zuqEd38/s1600/456.jpg" height="116" width="400" /></a></div>
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<o:p><br /></o:p></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi-YLZ40dFH3MWI6qHt4v9YyEwAw3eVDPDb6yMtJwGo4k9FKlS1LIpAj4Abd-tPPv6Cw-p_04euW7LVMOTi8iJXg9B-TMSwhTAgIhcMygMhvefUqm_dVAyVWmdhD0xVxxpIgNGIwTUOthY/s1600/m2.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi-YLZ40dFH3MWI6qHt4v9YyEwAw3eVDPDb6yMtJwGo4k9FKlS1LIpAj4Abd-tPPv6Cw-p_04euW7LVMOTi8iJXg9B-TMSwhTAgIhcMygMhvefUqm_dVAyVWmdhD0xVxxpIgNGIwTUOthY/s1600/m2.jpg" height="246" width="400" /></a></div>
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b) Calcula la V con la que impactará contra el muro si la distancia que recorre por el camino de barro es de 5 m.</div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi3w_MNLgi-Ab1yyLWfWsz0ytJHI8qX7oVT6NdmHwtPTFHod2wuQvVovWOapdtSpuIYAkK7UiRk6HTYL5Q3pa4UGIDUrkylcysmKPk9Cj9yb86hx2-gNHb5MWDCrJVCm9kbSfulkA3LaYk/s1600/m32.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi3w_MNLgi-Ab1yyLWfWsz0ytJHI8qX7oVT6NdmHwtPTFHod2wuQvVovWOapdtSpuIYAkK7UiRk6HTYL5Q3pa4UGIDUrkylcysmKPk9Cj9yb86hx2-gNHb5MWDCrJVCm9kbSfulkA3LaYk/s1600/m32.jpg" height="123" width="320" /></a></div>
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c) Calcula a y b para una pendiente del 100%</div>
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<b><u><br /></u></b></div>
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<b><u>SOLUCIÓN</u></b></div>
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<b><u><br /></u></b></div>
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a) <span style="text-align: center;">Calcula el t que tarda en recorrer la rampa.</span></div>
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<br /></div>
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TRAMO A-B</div>
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Primero hallamos la distancia que recorrerá el vehículo:</div>
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Nos dice que existe una pte del 80%:</div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgsk6b178TAF1Cl3E3lQldV4zsEDs69xfLfaSqBrKNxByJ-k1xVBYTu5Ot1NksJtKsjo8cOII3uh3bf-ftyMp4rN1-gHUSV7SlA6GsqYQcGKQ9vWZTw74uAz3kTW-pwOzj1rz5HaG1KIaM/s1600/697.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgsk6b178TAF1Cl3E3lQldV4zsEDs69xfLfaSqBrKNxByJ-k1xVBYTu5Ot1NksJtKsjo8cOII3uh3bf-ftyMp4rN1-gHUSV7SlA6GsqYQcGKQ9vWZTw74uAz3kTW-pwOzj1rz5HaG1KIaM/s1600/697.jpg" height="229" width="320" /></a></div>
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<span style="font-family: "Calibri","sans-serif"; font-size: 11.0pt; line-height: 115%; mso-ansi-language: ES; mso-ascii-theme-font: minor-latin; mso-bidi-font-family: "Times New Roman"; mso-bidi-language: AR-SA; mso-bidi-theme-font: minor-bidi; mso-fareast-font-family: Calibri; mso-fareast-language: EN-US; mso-fareast-theme-font: minor-latin; mso-hansi-theme-font: minor-latin;">tg α = 80/100 = 0,8</span></div>
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<span style="font-family: "Calibri","sans-serif"; font-size: 11.0pt; line-height: 115%; mso-ansi-language: ES; mso-ascii-theme-font: minor-latin; mso-bidi-font-family: "Times New Roman"; mso-bidi-language: AR-SA; mso-bidi-theme-font: minor-bidi; mso-fareast-font-family: Calibri; mso-fareast-language: EN-US; mso-fareast-theme-font: minor-latin; mso-hansi-theme-font: minor-latin;"><br /></span></div>
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<span style="font-family: "Calibri","sans-serif"; font-size: 11.0pt; line-height: 115%; mso-ansi-language: ES; mso-ascii-theme-font: minor-latin; mso-bidi-font-family: "Times New Roman"; mso-bidi-language: AR-SA; mso-bidi-theme-font: minor-bidi; mso-fareast-font-family: Calibri; mso-fareast-language: EN-US; mso-fareast-theme-font: minor-latin; mso-hansi-theme-font: minor-latin;">tg</span><span style="font-family: Calibri, sans-serif; font-size: 11pt; line-height: 115%; vertical-align: super;">-1 </span><span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">0,12 </span><span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">=</span><span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;"> 38,66</span><span style="font-family: Calibri, sans-serif; font-size: 11pt; line-height: 115%;">°</span><span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;"> </span></div>
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<span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">α = </span>38°39'35.31"</div>
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sen 38°39'35.31"= 0,62</div>
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cos 38°39'35.31"= 0,78</div>
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sen <span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">α</span> = 10/ distancia</div>
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distancia = 10/0,62 = 16,13 m </div>
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<o:p></o:p></div>
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<span style="font-family: "Calibri","sans-serif"; font-size: 11.0pt; line-height: 115%; mso-ansi-language: ES; mso-ascii-theme-font: minor-latin; mso-bidi-font-family: "Times New Roman"; mso-bidi-language: AR-SA; mso-bidi-theme-font: minor-bidi; mso-fareast-font-family: Calibri; mso-fareast-language: EN-US; mso-fareast-theme-font: minor-latin; mso-hansi-theme-font: minor-latin;"><br /></span></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhXM0N23Y2UA2yH1aZ2lJuef3N4HooGLAlStjw57m04nbXasdPTwyUd9VHtmjj0l2nNXSpvFs0NoSKk-8DqSnQ77iU-T8i1AW7zpiqxUTWJ8O75dr_d4Xx9lJYef4TvuC4U51bxCeza4Ho/s1600/1.1.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhXM0N23Y2UA2yH1aZ2lJuef3N4HooGLAlStjw57m04nbXasdPTwyUd9VHtmjj0l2nNXSpvFs0NoSKk-8DqSnQ77iU-T8i1AW7zpiqxUTWJ8O75dr_d4Xx9lJYef4TvuC4U51bxCeza4Ho/s1600/1.1.jpg" height="300" width="320" /></a></div>
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Necesitamos hallar la aceleración</div>
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<b><u><span style="font-size: large;">Px - Fr = m x a</span></u></b></div>
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<b> Px = m x g x sen <span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">α</span></b></div>
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<b> </b> Fr = μ x N = μ x m x g x cos α</div>
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<span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">m x g x sen </span><span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">α - </span>μ x m x g x cos α <span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">= m x a</span></div>
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<span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">Las masas se nos van:</span></div>
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<span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">g x sen </span><span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">α</span> - μ x g x cos α <span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">= a</span></div>
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<span style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">9,8 x 0,62 - ( 0,7 x 9,8 x 0,78) = a</span></div>
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<span style="font-family: Calibri, sans-serif;"><span style="font-size: 14.6666669845581px; line-height: 16.8666667938232px;"><b>a = 0,73 m/s²</b></span></span></div>
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<b style="font-family: Calibri, sans-serif; font-size: 14.6666669845581px; line-height: 16.8666667938232px;">El espacio que recorre el vehículo lo hemos calculado anteriormente:</b></div>
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S = S<sub>0</sub>+ V<sub>0</sub>t + ½ at²<o:p></o:p></div>
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16,13 = 1/2 x 0,73 x t² </div>
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<span style="font-size: large;"><u>t = 6,65 s</u></span></div>
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b) <span style="text-align: center;">Calcula la V con la que impactará contra el muro si la distancia que recorre por el camino de barro es de 5 m. </span></div>
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<span style="text-align: center;">TRAMO B-C</span></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh7XQWhCPDn7_hQldaWrtn5a3Lgd8hppqGUFEhPstG5Unfd9DNxzFzEeH6fvrKP-7VjCdveXIViyM9drvSKpM8efqAWwymLqO-H9VjfH2CLB6qhFnDZ4Uk-YKwBOLjJFB-2pwSJb5vcQes/s1600/22254.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh7XQWhCPDn7_hQldaWrtn5a3Lgd8hppqGUFEhPstG5Unfd9DNxzFzEeH6fvrKP-7VjCdveXIViyM9drvSKpM8efqAWwymLqO-H9VjfH2CLB6qhFnDZ4Uk-YKwBOLjJFB-2pwSJb5vcQes/s1600/22254.jpg" height="170" width="400" /></a><br />
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Cambian las fuerzas, por lo que cambia la aceleración</div>
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OJO: El vehiculo circula por una superficie con distinto coeficiente de rozamiento!!!</div>
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<b><span style="font-size: large;">-Fr = m x a </span></b></div>
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- μ x m x g = m x a</div>
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Se van las masas:</div>
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-0,2 x 9,8 = a</div>
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a= -1,96 m/s²</div>
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Calculamos la Vf del tramo A-B que será la V0 del tramo B-C</div>
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Vf = V0 + at </div>
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Vf = 0 + 0,73 x 6,65 = 4,85 m/s</div>
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Calculamos Vf para el tramos B-C</div>
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Vf ² - V<sub>0</sub>² = 2a (S -S<sub>0)</sub></div>
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<sub><span style="font-size: small;">Vf² = 2x (-1,96) x 5 +4,85²</span></sub></div>
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<sub><span style="font-size: small;">Vf= 3,92 m/s</span></sub></div>
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<sub><span style="font-size: small;">Vf = 14,11 km/h</span></sub></div>
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<sub><a href="https://drive.google.com/file/d/0B-w039OFBj-1eDVoc0IxSUVWcG8/view?usp=sharing" target="_blank">https://drive.google.com/file/d/0B-w039OFBj-1eDVoc0IxSUVWcG8/view?usp=sharing</a></sub></div>
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Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-84076608083904776072015-03-22T21:56:00.000+01:002015-04-19T18:39:39.419+02:00ACERTIJO TIPO PUZZLE<a href="http://matematicascercanas.com/2015/03/17/a-dividir-en-partes-iguales/" target="_blank">http://matematicascercanas.com/2015/03/17/a-dividir-en-partes-iguales/</a>Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-9270956431893175142015-03-20T13:44:00.003+01:002015-03-20T13:45:18.221+01:00EL TRUCO DEL CHOCOLATE INFINITO<a href="https://es.tiching.com/el-truco-del-chocolate-infinito/recurso-educativo/682028" target="_blank">https://es.tiching.com/el-truco-del-chocolate-infinito/recurso-educativo/682028</a>Anonymoushttp://www.blogger.com/profile/15425873666541225166noreply@blogger.com0tag:blogger.com,1999:blog-3629677898726119344.post-3724203884165372322015-03-19T20:45:00.000+01:002015-03-20T00:38:43.466+01:00HOJAS RESUMEN MATEMÁTICAS PARA TENER A MANO!!!<br />
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